A golf ball is struck with a velocity of 80 ft/s as shown. Determine the speed at which it strikes the ground at b and the time of flight from a to b

Speed at which it strikes the ground = 67.4ft/s

Time of flight = 3.57secs

Explanation:

(Va) x = 80cos (10+45) ° = 44.886

(Va) y = 80sin (10+45) ° = 65.532

S=So + Vot + 1/2at^2

d sin 10° = 0 + 65.532t + 1/2 (-32.2) t^2

0.17d = 0 + 65.532t + (-16.1) t^2

Solving the equation gives

d=166ft

t = 3.57seconds

(Vb) x = (Va) x = 45.886

(Vb) y = 65.532 - 32.2 (3.57)

(Vb) y = - 49.357

Vb = sqrt (45.886^2 + (-49.357^2))

Vb = 67.4ft/s