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11 February, 09:48

An object of mass 0.40 kg, hanging from a spring with a spring constant of 8.0 N/m, is set into an up-and-down simple harmonic motion. What is the magnitude of the acceleration of the object when it is at its maximum displacement of 0.10 m?

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  1. 11 February, 10:55
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    a = 2 m/s2

    Explanation:

    we know from newtons 2nd law

    F = ma.

    we also know that from hookes law we have

    F = kx

    equate both value of force to get value of acceleration

    kx = ma,

    where,

    k is spring constant = 8.0 N/m

    x is maximum displacement 0.10 m

    m is mass of object 0.40 kg

    a = / frac{kx}{m}

    = / frac{8 * 0.10}{0.40}

    a = 2 m/s2
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