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12 November, 14:31

A 1.2 kg block of wood hangs motionless from strings. A 50 gram bullet, traveling horzontally, strikes the block and becomes embedded inside the block. Immediately after the bullet becomes embedded in the block, the block is observed to have a speed of 8.0 m/s. What was the speed of the bullet before it hit the block

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  1. 12 November, 17:02
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    speed of the bullet before it hit the block is 200 m/s

    Explanation:

    given data

    mass of block m1 = 1.2 kg

    mass of bullet m2 = 50 gram = 0.05 kg

    combine speed V = 8.0 m/s

    to find out

    speed of the bullet before it hit the block

    solution

    we will apply here conservation of momentum that is

    m1 * v1 + m2 * v2 = M * V ... 1

    here m1 is mass of block and m2 is mass of bullet and v1 is initial speed of block i. e 0 and v2 is initial speed of bullet and M is combine mass of block and bullet and V is combine speed of block and bullet

    put all value in equation 1

    m1 * v1 + m2 * v2 = M * V

    1.2 * 0 + 0.05 * v2 = (1.2 + 0.05) * 8

    solve it we get

    v2 = 200 m/s

    so speed of the bullet before it hit the block is 200 m/s
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