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2. Can you place three forces of 5g, 6g, and 12g so they are in equilibrium. Justify your answer.

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  1. Today, 10:08
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    We cannot place three forces of 5g, 6g, and 12g in equilibrium.

    Explanation:

    Equilibrium means their sum must be zero.

    Here the forces are 5g, 6g, and 12g.

    For number of forces to be in equilibrium the magnitude of largest vector should be less than sum of the magnitude of other vectors.

    Here

    Magnitude of largest force = 12 g

    Sum of magnitudes of other forces = 5g + 6g = 11g

    Magnitude of largest force > Sum of magnitudes of other forces

    So this forces cannot form equilibrium.

    We cannot place three forces of 5g, 6g, and 12g in equilibrium.
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