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20 April, 11:53

The nonreflective coating on a camera lens with an index of refraction of 1.29 is designed to minimize the reflection of 634-nm light. If the lens glass has an index of refraction of 1.53, what is the minimum thickness of the coating that will accomplish this task?

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  1. 20 April, 15:52
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    minimum thickness of the coating = 122.868 nm

    Explanation:

    Given data

    lens index of refraction = 1.29

    wavelength = 634 nm

    glass index of refraction = 1.53

    to find out

    minimum thickness of the coating

    solution

    we have given non reflective coating

    so

    we know that minimum thickness of the coating formula

    minimum thickness of the coating = Wavelength / 4n

    here n is coating index of refraction

    so put here both value to get thickness

    minimum thickness of the coating = Wavelength / 4n

    minimum thickness of the coating = 634 / 4 (1.29)

    so minimum thickness of the coating = 122.868 nm
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