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28 January, 06:24

Now imagine a person dragging a 50 kg box along the ground with a rope, as

in the drawing below. The person exerts 50 N of force while moving the box 201

10 s. Suppose also that friction is acting with 30 N of force between the box and the

ground

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Answers (1)
  1. 28 January, 06:51
    0
    The coefficient of static friction between the box and floor is, μ = 0.061

    Explanation:

    Given data,

    The mass of the box, m = 50 kg

    The force exerted by the person, F = 50 N

    The time period of motion, t = 10 s

    The frictional force acting on the box, f = 30 N

    The normal force on the box, η = mg

    = 50 x 9.8

    = 490 N

    The coefficient of friction,

    μ = f / η

    = 30 / 490

    = 0.061

    Hence, the coefficient of static friction between the box and floor is, μ = 0.061
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