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27 May, 03:36

What is the index of refraction of a material for which the wavelength of light is 0.6024 times its value in a vacuum? Identify the likely substance

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  1. 27 May, 04:04
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    1.66, This value corresponds to flint glass.

    Explanation:

    Refractive index is equal to velocity of the light 'c' in empty space divided by the velocity 'v' in the substance.

    Or,

    n = c/v.

    Also,

    c = frequency * Wavelength

    The formula can be written as:

    n = λ / λn.

    Where,

    λn is the wavelength in the medium

    λ is the wavelength in vaccum

    Given that: λn = 0.6024 λ

    So, n is:

    n = λ / λn = λ / 0.6024 λ = 1.66

    This value corresponds to flint glass.
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