A - 1.12 μC charge is placed at the center of a conducting spherical shell, and a total charge of + 8.65 μC is placed on the shell itself. Calculate the total charge on the outer surface of the conductor.

Answer: 7.53 μC

Explanation: In order to explain this problem we have to use the gaussian law so we have:

∫E. dS=Qinside/εo we consider a gaussian surface inside the conducting spherical shell so E=0

Q inside = 0 = q + Qinner surface=0

Q inner surface = 1.12μC so in the outer surface the charge is (8.65-1.12) μC=7.53μC