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15 September, 07:50

If the torque required to loosen a nut that is holding a flat tire in place on a car has a magnitude of 33 N · m, what minimum force must be exerted by the mechanic at the end of a 30 cm-long wrench to loosen the nut?

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Answers (2)
  1. 15 September, 10:29
    0
    110 N.

    Explanation:

    Torque = F * (d sin θ)

    Where,

    F = force applied

    d = distance perpendicular to the force applied.

    Minimum force applied is at 90° to the force. Therefore,

    Torque = F * (d sin 90°)

    33 = F * (0.3 * 1)

    = 33/0.3

    = 110 N.
  2. 15 September, 10:30
    0
    The minimum force that must be exerted by the mechanic at the end of a 30 cm-long wrench to loosen the nut is 110N

    Explanation:

    Torque = Fd sin θ

    For a torque, the minimum force must be applied perpendicular to the lever arm, so that θ = 90° and sin θ = sin 90° = 1

    Torque = 33 N. m

    F = Force applied = ?

    d = 30 cm = 0.3 m

    F = Torque/d = 33/0.3 = 110 N
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