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12 November, 20:30

A 20-kilogram box is sitting on an inclined plane with a 30-degree slope. If the box is at rest, what is the force

on the box due to friction?

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  1. 12 November, 23:59
    0
    The box is at rest because, the component of weight along the surface downwards is equal to frictional force.

    frictional force = mgsinθ

    = 20 x 9.8 sin 30

    = 98 N.
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