When the pumpkin is shot straight upward with an initial speed of 14 m/s, what is the maximum height above its initial equation

Question

Physics

Johanna Campos

7 May, 03:41

When the pumpkin is shot straight upward with an initial speed of 14 m/s, what is the maximum height above its initial equation

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Answers (1)

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Ari Adams · Answer 1

10 m

Explanation:

At the maximum height, the velocity is 0.

Given:

v₀ = 14 m/s

v = 0 m/s

a = - 9.8 m/s²

Find: Δy

v² = v₀² + 2aΔy

(0 m/s) ² = (14 m/s) ² + 2 (-9.8 m/s²) Δy

Δy = 10 m