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2 August, 13:13

A train moving with an initial velocity of 20 m/s accelerated at 4 m/s^2 for 10 seconds. During this time, the train moves a distance of how many meters

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  1. 2 August, 13:58
    0
    400 m

    Explanation:

    Given:

    v₀ = 20 m/s

    a = 4 m/s²

    t = 10 s

    Find: Δx

    Δx = v₀ t + ½ at²

    Δx = (20 m/s) (10 s) + ½ (4 m/s²) (10 s) ²

    Δx = 400 m
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