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24 April, 21:37

When the pad is replaced by one that requires a distance of 4d to stop the same package, what happens to the length of time it takes for the package to stop?

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  1. 24 April, 22:07
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    t = 4 t₁, We see that time is increased by a factor of 4

    Explanation:

    For this exercise let's use the concepts of kinematics

    v² = v₀² + 2 a d

    With the first pad when the package stopped zero speed, let's look for acceleration

    0 = v₀² - 2 a₁ d

    a₁ = v₀² / 2 d

    Let's use the equation to enter time

    v = v₀ - a₁ t₁

    t₁ = v₀ / a₁

    When we replace the pad with another one where the distance is 4d

    a = v₀² / 2 (4d)

    a = a₁ / 4

    We see that the acceleration is 4 times lower.

    The equation kinematics

    v = v₀ - at

    t = v₀ / a

    We replace the acceleration

    t = v₀ 4/a1

    t = t₁ 4

    We see that time is increased by a factor of 4
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