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19 June, 03:39

A particle is moving in a straight line. at t second, it acceleration is (4-kt), where k is a constant. when t=6, the acceleration of a particle is zero determine its velocity as a function of time

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  1. 19 June, 05:17
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    v = 4t - t²/3

    Explanation:

    4 - k*6 = 0

    k = 4/6 = 2/3

    dv/dt = 4 - 2/3 t

    integral of dv = integral of (4-2/3 t) dt

    v = 4t - t²/3
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