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24 December, 12:30

Two parakeets sit on a swing with their combined center of mass 10.0 cm below the pivot. At what frequency do they swing?

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  1. 24 December, 16:20
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    1.58 Hz

    Explanation:

    The frequency of the simple pendulum is given by

    f = 1/T

    = 1/2π√g/l

    In this problem, I = 10.0 cm = 0.1 m

    f = 1/2π√9.8/0.1

    = 1.58 Hz
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