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21 April, 11:48

The specific angular momentum of a spacecraft in circular Earth orbit is 48,000 km2 / s. Determine the period of the orbit.

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  1. 21 April, 15:32
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    T = 5325 s

    Explanation:

    Given:

    - Specific angular momentum h = 48,000 km^2 / s

    - Radius of earth r_e = 6.3781 * 10^3 km

    Find:

    The period of orbit

    The relationship between Specific angular momentum h and period of orbit is as follows:

    h = 2*pi*r_e^2 / T

    T = 2*pi*r_e^2 / h

    Hence, Plug the values

    T = 2*pi * (6.3781 * 10^3) ^2 / 48,000

    T = 5325 s = 1.48 h
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