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10 December, 17:37

A 45 kg student runs up a flight of stairs that are 3.2 m high in 2 seconds. How much power did the student use during this time?

706 W

288 W

72 W

7.0 W

+3
Answers (2)
  1. 10 December, 17:54
    0
    Power=Work/time.

    In this case Work=increase in potential energy.

    Supposing he was initially on the floor, W=mgh=45*9.8*3.2=1411.2 J.

    Therefore

    Power=1411.2/2=705.6≈706 W.
  2. 10 December, 18:42
    0
    Power = work done/time. Work done by gravity = mgh = 45x9.8x3.2 = 1411.2J. Therefore, power = 1411.2/2 = 705.6 ~ 706W.
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