A stone is thrown vertically upward with velocity 9.8ms 1) calculate the time taken to reach maximum height. 2) what is the maximum height reached 3) what is time taken to reach ground 4) what velocity it reaches the ground

It would take 6 seconds before hitting the ground

1. t=-1.96sec

2. H=4.8m

3. T=1.96sec

4. R=19.2m

Explanation:

u=9.8, t=?, sin theta=1

using formula t=2usintheta/g

t=2x9.8x1=19.6/10

t=1.96seconds

using formula H=u (squared) sin (squared) theta/2g

H=9.8 (squared) x1 (squared) / 2x10

H=96x1/20

H=96/20

H=4.8m

using formula T=2usintheta/g

T=2x9.8x1/10

T=19.6/10

T=1.96sec

using the formula R=u (squared) sin2theta/g

R=9.8 (squared) x2/10

R=96x2/10

R=192.08/10

R=19.2