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5 August, 23:56

A 40 cm wire with a radius of 3 cm is oriented along the y axis and carries a current of 2 A. What is the magnitude of the magnetic field 2 cm from the center of the wire? A 40 cm wire with a radius of 3 cm is oriented along the y axis and carries a current of 2 A. What is the magnitude of the magnetic field 4 cm from the center of the wire

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  1. 6 August, 03:08
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    a) B = 1.99 x 10⁻⁴ Tesla

    b) B = 0.88 x 10⁻⁴ Tesla

    Explanation:

    According to Biot - Savart Law, the magnetic field due to a currnt carrying straight wire is given as:

    B = μ₀ I L/4πr²

    where,

    μ₀ = permebility of free space = 1.25 x 10⁻⁶ H m⁻¹

    I = current = 2 A

    L = Length of wire = 40 cm = 0.4 m

    a)

    r = radius of magnetic field = 2 cm = 0.02 m

    Therefore,

    B = (1.25 x 10⁻⁶ H m⁻¹) (2 A) (0.4 m) / 4π (0.02 m) ²

    B = 1.99 x 10⁻⁴ Tesla

    b)

    r = radius of magnetic field = 3 cm = 0.03 m

    Therefore,

    B = (1.25 x 10⁻⁶ H m⁻¹) (2 A) (0.4 m) / 4π (0.03 m) ²

    B = 0.88 x 10⁻⁴ Tesla
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