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27 May, 15:17

a baseball pitcher loosens up his pitching arm. he tosses a 0.140 kg ball using only the roation of his forearm, 0.270m in length, to accerlate the ball. if the ball starts at rest and is releasedwith a speed of 24 in a time of 0.425, what torque is applied to the ball

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  1. 27 May, 15:43
    0
    2.136 N-m

    Explanation:

    From the question,

    Applying,

    Toque = FL ... Equation 1

    Where F = Force applied to the the ball, L = Length of the forearm

    From newton's second law of motion,

    F = m (v-u) / t ... Equation 2

    Where m = mass of the ball, v = final velocity of the ball, u = initial velocity of the ball, t = time.

    Given: m = 0.140 kg, u = 0 m/s (from rest), v = 24 m/s, t = 0.425 s

    Substitute into equation 2

    F = 0.140 (24-0) / 0.425

    F = 7.91 N.

    Also Given: L = 0.270 m

    Substitute into equation 1

    Torque = 7.91*0.270

    Torque = 2.136 N-m
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