An inductor is connected to an AC power supply having a maximum output voltage of 3.00 V at a frequency of 280 Hz. What inductance is needed to keep the rms current less than 2.50 mA? (Provide the minimum value.)

L = 0.48 H

Explanation:

let L be the inductance, Irms be the rms current, Vrms be the rms voltage and Vmax be the maximum voltage and XL be the be the reactance of the inductor.

Vrms = Vmax / (√2)

= (3.00) / (√2)

= 2.121 V

then:

XL = Vrms/I

= (2.121) / (2.50*10^-3)

= 848.528 V/A

that is L = XL / (2*π*f)

= (848.528) / (2*π * (280))

= 0.482 H

Therefore, the inductance needed to kepp the rms current less than 2.50mA is 0.482 H.