A 1790 kg car has just passed a diner. The closest the car came to the diner was R=28.5 m, but the car has driven another x=42.7 m in the 2.85 s2.85 s elapsed since then. If the car travels at constant speed, what is the current magnitude of the angular momentum of the car about the diner?

Question

Physics

Hadassah Jones

18 November, 23:31

A 1790 kg car has just passed a diner. The closest the car came to the diner was R=28.5 m, but the car has driven another x=42.7 m in the 2.85 s2.85 s elapsed since then. If the car travels at constant speed, what is the current magnitude of the angular momentum of the car about the diner?

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Answers (1)

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Hamza Gross · Answer 1

6208270.4 kg. m^2/s^1

Explanation:

let X = x = 42.7 m and t = 2.85s

the speed of the car, v = X*t

= 42.7*2.85

= 121.695 m/s

then, we know that the angular momentum is given by:

when the is just passing the dinner, the distance from the diner to the car is perpendicular to the cars trajectory.

L = m*R*v, where R is the perpendicular distance.

= 1790*28.5*121.695

= 6208270.4 kg. m^2/s^1