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29 December, 09:45

A 40-kilogram crate is at rest on a level surface. If the coefficient of static friction between the crate and the surface is 0.69, what horizontal force is required to get the crate moving?

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  1. 29 December, 12:03
    0
    270.8 N

    Explanation:

    y axis:

    N-w=0

    N=mg = 40*9.81 = 392.4 N

    x axis:

    P - fs = 0

    p = meo * N = 0.69 * 392.4 = 270.8 N (ans)
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