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1 August, 17:28

Suppose a 48-N sled is resting on packed snow. The coefficient of kinetic friction is 0.10. If a person weighing 660 N sits on the sled, what force is needed to pull the sled across the snow at constant speed?

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  1. 1 August, 19:00
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    Assume the snow is uniform, and horizontal.

    Given:

    coefficient of kinetic friction = 0.10 = muK

    weight of sled = 48 N

    weight of rider = 660 N

    normal force on of sled with rider = 48+660 N = 708 N = N

    Force required to maintain a uniform speed

    = coefficient of kinetic friction * normal force

    = muK * N

    = 0.10 * 708 N

    =70.8 N

    Note: it takes more than 70.8 N to start the sled in motion, because static friction is in general greater than kinetic friction.
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