Ask Question
17 March, 18:33

A ray of light traveling in air strikes the surface of a liquid. if the angle of incidence is 31.7◦ and the angle of refraction is 21.3◦, find the critical angle for light traveling from the liquid back into the air. answer in units of ◦.

+3
Answers (1)
  1. 17 March, 19:53
    0
    Media 1 and 2 are air and liquid. By Snell's law;

    n1/n2 = Sin ∅2/Sin ∅1

    Then,

    n2 = (n1 * Sin Ф1) / Sin ∅2 = (1*Sin 31.7) / Sin 21.3 = 1.4466.

    When the light travels in the opposite direction and at critical angle, media 1 and 2 are liquid and air respectively while ∅2 = 90°

    Therefore,

    n1/n2 = Sin 90 / Sin ∅c = > ∅c = Sin ^-1[n2*Sin 90]/n1 = Sin ^-1[1*Sin 90]/1.4466 = 43.73°

    The critical angle (∅c) is 43.73°.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A ray of light traveling in air strikes the surface of a liquid. if the angle of incidence is 31.7◦ and the angle of refraction is 21.3◦, ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers