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2 March, 13:22

a supertanker traveling at 7.2 m/s (about 12 mph) decelerates to a halt in 12 min. Calculate the magnitude of its average deceleration in meters per second squared.

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  1. 2 March, 14:37
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    Answer: 0.01 m/s2

    Explanation:

    Given that:

    Velocity of supertanker = 7.2 m/s (about 12 mph)

    Time taken = 12 min

    (Since the SI unit of time is seconds, convert 12 minutes to seconds

    1 minute = 60 seconds

    12 minutes = 12 x 60 = 720 seconds)

    Average deceleration = ?

    Recall that deceleration is obtained by dividing velocity by time taken.

    i. e Deceleration = velocity / time

    Deceleration = 7.2 m/s / 720 seconds

    = 0.01 m/s2

    Thus, the magnitude of its average deceleration is 0.01 meters per second squared.
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