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26 June, 20:04

The spin-drier of a washing machine revolving at 900. RPM slows down uniformly to 300. RPM while making 60. revolutions. Find the angular acceleration and the time required to turn through these 60. revolutions.

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  1. 26 June, 23:40
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    Acceleration is - 10.57 rad/s²

    Time is 6 seconds

    Explanation:a)

    u=900rpm = 94.248 rad/s

    v = 300rpm = 31.416 rad/s

    s=60 revolutions = 377 rad

    v² = u² + 2as

    31.416² = 94.248² + 2 * a * 377

    a = v²-u² / 2s

    a = - 10.57 rad/s²

    b)

    Using 1st equation of motion

    v-u/a = t

    Putting the values

    t = (31.4 - 94.2) / -10.57

    t = 6 seconds
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