The student moves his leg 34 cm sideways as shown.

The average resistance force is 23 N.

(a) (i) State the relationship between work done, force and distance moved.

(1)

(ii) Calculate the work done when the student moves his leg sideways once.

Question A1:

Workdone=force x distance

Question A11:

7.82 joules

Explanation:

question A1:

The relationship between work done, force and distance is that workdone can be calculated by multiplying force and distance

Question A11:

Force=23N

Distance=34cm=0.34m

Work done=force x distance

Work done=23 x 0.34

Workdone=7.82J

(i) • there is force applied to an objects

• the object moves

• the object moves in the same direction as the direction of the force

(ii) workdone = force x distance

= 23 x 34

= 782Joules