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9 November, 22:05

A galvanometer with a resistance of 40.0 ω deflects full scale at a current of 2.0 ma. what resistance should be used with this galvanometer in order to construct a voltmeter that can read a maximum of 50 v?

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  1. 10 November, 00:31
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    The resistance needed to be added is R

    The Current is 2 ma

    The voltage reading is a maximum of 50 volts.

    The ma meter has an internal resistance of 40 ohms.

    Formula

    E = I * R

    Givens

    E = 50

    I = 2 ms

    R = R + 40

    Solution

    E = I * R

    I = 2 ma [ 1 amp / 1000 ma] = 0.002 amp

    50 = 0.002 * (R + 40) Divide by 0.002

    50/0.002 = R + 40

    25000 = R + 40 Subtract 40 from both sides.

    R = 25000 - 40

    R = 24960 Answer
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