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2 October, 14:23

A bicyclist bikes the 56 mi to a city averaging a certain speed. The return trip is made at a speed that is 6 mph slower. Total time for the round trip is 11 hr. Find the bicyclist's average speed on each part of the trip.

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  1. 2 October, 15:30
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    Speed of the bicyclist when going to city = 14 miles per hour.

    Speed while return trip = 8 miles per hour.

    Explanation:

    Let the speed of the bicyclist when going to city = x miles per hour.

    Speed while return trip = x - 6 miles per hour.

    Total time taken = 11 hrs = Time for the trip to city + time taken for return trip.

    Also, Time = Distance / Time.

    So,

    56 / x + 56 / (x - 6) = 11

    11x² - 178x + 336 = 0

    Solving for x we get:

    Acceptable x = 14 miles per hour.

    Speed while return trip = x - 6 miles per hour = 8 miles per hour.
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