A 50 Kg box sits at rest on a 30 degree ramp where the coef of static friction is 0.5773 what is the weight of the box?

Given dа ta:

mass (m) = 50 Kg

W = m*g = 50*9.81 = 490.5 N

Coefficient of static friction (μs) = 0.5773

ramp angle = 30 degrees

determine Normal force=?

From the figure we know that

Normal force (N) = μs. W cosΘ

= 0.5773 * 490.5*cos 30

= 245.22 N

Therefore, The Normal force = 245.23 N