A ring of mass 32 kg has an angular velocity of 110 rad/s. The radius of the ring is 0.380 m. What is the rotational kinetic energy of the ring?

Question

Physics

Payton Rocha

22 February, 12:38

A ring of mass 32 kg has an angular velocity of 110 rad/s. The radius of the ring is 0.380 m. What is the rotational kinetic energy of the ring?

+1

Answers (1)

Know the Answer?

Irene Lam · Answer 1

Answer: 2.8 kJ

Explanation: Given that

The mass M = 32 kg

w = 110 rad/s

r = 0.380 m

Rotational kinetic energy = 1/2 Iw^2

Where I = moment of inertia

I = Σ mr^2

I = 32 * 0.38^2

I = 4.6208

Rotational K. E = 1/2 * 4.6208 * 110^2

Rotational K. E = 27955.84 J

= 2.8 KJ approximately