Ask Question
2 July, 10:43

A shopper pushes a 5.32 kg grocery cart with a 12.7 N force directed at - 28.7° below horizontal. A friction force of 8.33 N pushes back against the motion.

What is the acceleration of the cart?

+1
Answers (1)
  1. 2 July, 14:36
    0
    0.8214 m/s^2

    Explanation:

    Fnet = Fpushed - Ffriction

    Fpushed = 12.7N Ffriction = 8.33N

    Fnet = 12.7N - 8.33N = 4.37N

    Fnet = mass (acceleration)

    Fnet = 4.37N mass = 5.32 kg

    4.37N = 5.32 kg (acceleration)

    acceleration = 0.8214 m/s^2
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A shopper pushes a 5.32 kg grocery cart with a 12.7 N force directed at - 28.7° below horizontal. A friction force of 8.33 N pushes back ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers