A ball dropped from a bridge takes three seconds to reach the water below how far is the bridge above the water?

Given that:

Ball dropped from a bridge at the rate of 3 seconds

Determine the height of fall (S) = ?

As we know that, S = ut + 1/2 * a. t²

u = initial velocity = 0

a = g = 9.81 m/s (since free fall)

S = 0 + 1/2 * 9.81 * 3²

S = 44.145 m

44.145 m far is the bridge from water