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28 January, 09:29

A conducting rod (length = 80 cm) rotates at a constant angular rate of 15 revolutions per second about a pivot at one end. A uniform field (B = 60 mT) is directed perpendicularly to the plane of rotation. What is the magnitude of the emf induced between the ends of the rod?

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  1. 28 January, 11:44
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    3.62 V

    Explanation:

    L = 80 cm = 0.8 m

    f = 15 rps

    B = 60 m T = 0.060 T

    ω = 2 x π x f = 2 x 3.14 x 15 = 94.2 rad/s

    v = r ω

    here, r be the radius of circular path. Here r = length of rod = L

    v = 0.80 x 94.2 = 75.36 m/s

    The motional emf is given by

    e = B v L = 0.060 x 75.36 x 0.8 = 3.62 V
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