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6 June, 15:12

A rock is thrown upward with a velocity of 23 meters per second from the top of a 25 meter high cliff, and it misses the cliff on the way back down. when will the rock be 11 meters from the water, below

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  1. 6 June, 18:55
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    Vf=vi+at

    -23m/s=23m/s-9.8m/s^2 (t)

    t1 from throwing up back to starting position t1=4.693s

    Delta (x) = vi (t) +.5a (t^2)

    25-11=14

    -14m=-23m/s (t) - 4.8m/s^s (t^2)

    t2 is from 25m to 11 m t2=.546s

    Total time = 5.239s
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