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10 February, 11:32

2) A sprig with a length of 15 cm and stores 110 J of potential energy when stretched to a new

length

If the sprig constant is 350 N/m. Find the new length of that spring

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Answers (1)
  1. 10 February, 15:11
    0
    94.28 cm

    Explanation:

    The formula for elastic potential energy is given as;

    PEel = 1/2 * k*x² where x is the displacement, k is the spring constant

    Given

    PEel = 110 J, k = 350 N/m then find x

    PEel = 1/2 * k*x²

    110 = 1/2 * 350 * x²

    110 = 175 x²

    110/175 = x²

    0.6286=x²

    √0.6286 = x

    0.7928 m = x

    79.28 cm = x

    New length of spring = 15 cm + 79.28 cm = 94.28 cm
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