Ask Question
10 February, 14:00

A free-falling projectile is launched from the ground and has a hangtime of 6 seconds before hitting the ground. How high did it go?

+3
Answers (1)
  1. 10 February, 14:55
    0
    1A)

    x=v0x*t=v0cosθ*t

    x=52co31*3.2=142.6 m

    1B)

    y0=1/2gt^2-v0y*t=1/2gt^2-v0sinθt

    y=0.5*9.8*3.2^2-52*sin31*3,2=23.4 m

    2A)

    x=2v0^2sin (2θ) / g

    v0=[xg/2sin (2θ) ]^1/2=14.4 m/s

    the initial speed relative to the ground is

    v=v0-4.4=10 m/s

    2B)

    fly time is

    t=2voy/g

    t=2*14.4/9.8=2.94

    2C)

    mgy=1/2mv0y^2

    y=v0y^2 / (2g) = 10.58 m
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A free-falling projectile is launched from the ground and has a hangtime of 6 seconds before hitting the ground. How high did it go? ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers