a car slows down - 27.7 m/s to - 10.9 m/s "while" undergoing a displacement of - 105 m what was its acceleration

Acceleration of car=3.09 m/s²

Explanation:

initial velocity = Vi=-27.7 m/s

Final velocity=-10.9 m/s

displacement=-105 m

using kinematic equation Vf² = Vi² + 2 a d

(-10.9) ² = (-27.7) ² + 2 a (-105)

-648.5=-210a

a=648.5/210

a=3.09 m/s²