the acceleration of a freely falling body is about 10m/sec/sec. if the ball is dropped from the top of a building what would its velocity be after 2 seconds?

The final velocity will be 20 m/s

Explanation:

According to first law of motion

Vf = Vi + at

Here we are given with

Vf = ?

Vi = 0 because it started from 0

a = 10 m/s²

t = 2 sec

So putting the values in the equation we get

Vf = 0 + 10 x 2

Vf = 20

So velocity after 2 seconds will be 20 m/s

The velocity will be 20 meters per second