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27 January, 13:23

If a rock weighing 2,200 N is dropped from a height of 15 m, what is its kenetic energy just before it hits the ground

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  1. 27 January, 16:18
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    Kinetic energy of the rock just before it hits the ground=KE=33000 J

    Explanation:

    Weight = 2200N

    mg=2200

    m (9.8) = 2200

    m=224.5 kg

    initial velocity=0

    final velocity = V

    using kinematic equation V²=Vi²+2gh

    V²=0+2 (9.8) (15)

    V=17.1 m/s

    now kinetic energy = 1/2 mV²

    KE = 1/2 (224.5) (17.1) ²

    KE=33000 J

    Thus the kinetic energy of the rock just before it hits the ground=33000 J
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