If a rock weighing 2,200 N is dropped from a height of 15 m, what is its kenetic energy just before it hits the ground

Kinetic energy of the rock just before it hits the ground=KE=33000 J

Explanation:

Weight = 2200N

mg=2200

m (9.8) = 2200

m=224.5 kg

initial velocity=0

final velocity = V

using kinematic equation V²=Vi²+2gh

V²=0+2 (9.8) (15)

V=17.1 m/s

now kinetic energy = 1/2 mV²

KE = 1/2 (224.5) (17.1) ²

KE=33000 J

Thus the kinetic energy of the rock just before it hits the ground=33000 J