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10 August, 13:40

A square current loop 5.20 cm on each side carries a 460 mA current. The loop is in a 0.900 T uniform magnetic field. The axis of the loop, perpendicular to the plane of the loop, is 30° away from the field direction.

What is the magnitude of the torque on the current loop?

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  1. 10 August, 13:51
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    The magnitude of the torque on the current loop is 0.0055 Nm

    Explanation:

    Given data,

    We have the formula,

    T = u x B

    Where u = i x A

    T = i*A*B * sin (30)

    T=0.46*0.52² * 0.900*0.5

    T=0.0055 Nm

    The magnitude of the torque on the current loop is 0.0055 Nm
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