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A satellite with a mass of 5.6 E 5 kg is orbiting the Earth in a circular path. Determine the satellite's velocity if it is orbiting at a distance of 9.8 E 5 m above the Earth's surface. Earth's mass = 5.98 E 24 kg; Earth's radius = 6.357 E 6 m.

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  1. Today, 10:23
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    7400 m/s

    Explanation:

    Centripetal acceleration = gravity

    v² / r = GM / r²

    v = √ (GM / r)

    Given:

    G = 6.67*10⁻¹¹ m³/kg/s²

    M = 5.98*10²⁴ kg

    r = 9.8*10⁵ + 6.357*10⁶ = 7.337*10⁶ m

    v = √ (6.67*10⁻¹¹ (5.98*10²⁴) / (7.337*10⁶))

    v = 7400

    The orbital velocity is 7400 m/s.
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