A rope exerts a 280 N force while pulling an 80 Kg skier upward along a hill inclined at 12o. The rope pulls parallel to the hill. The coefficient of friction between the skier and the hill is 0.15. If the skier starts from rest, determine her speed after moving 100 m up the slope.

The speed of the skier after moving 100 m up the slope are of V = 25.23 m/s.

Explanation:

F = 280 N

m = 80 kg

α = 12º

μ = 0.15

d = 100m

g = 9,8 m/s²

N = m*g*sin (α)

N = 163 Newtons

Fr = μ * N

Fr = 24.45 Newtons

∑F = m*a

a = (280N - 24.5N) / 80kg

a = 3.19 m/s²

d = a * t² / 2

t=√ (2*d/a)

t = 7.91 sec

V = a * t

V = 3.19 m/s² * 7.91 s

V = 25.23 m/s