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9 February, 16:58

if the mass of the marble is 0.025kg, and you assume that on the first drop of your roller coaster (height=8cm) the marble is falling at exactly the rate of gravity (9.8m/s^2), what is the force of the marble? What is its potential energy in the beginning?

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  1. 9 February, 18:26
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    1. What is the force of the marble?

    For an object near the surface of the earth, the gravitational force acting upon the object is given by:

    F = mg

    F is the gravitational force, m is the object's mass, and g is the acceleration of objects due to earth's gravity.

    Given values:

    m = 0.025kg, g = 9.8m/s²

    Plug in the given values and solve for F:

    F = 0.025*9.8

    F = 0.25N

    2. What is the marble's potential energy at the start of its fall?

    The gravitational potential energy of an object near the earth's surface is given by:

    PE = mgh

    PE is the potential energy, m is the object's mass, g is the acceleration of objects due to earth's gravity, and h is the object's relative height.

    new given values:

    h = 0.08m

    Since F = mg, you can simply multiply F*h to get PE. Use the result from question 1:

    PE = F*h

    PE = 0.25*0.08

    PE = 0.02J
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