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3 May, 20:46

In a nuclear reactor, each atom of uranium (of atomic mass 235 u) releases about 200 MeV when it fissions. What is the change in mass when 2.60 kg of uranium-235 is fissioned?

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  1. 3 May, 22:29
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    0.002372187708 kg

    Explanation:

    Each atom of Uranium 235 releases 200 MeV = 200*10⁶*1.60218*10⁻¹⁹

    = 200*1.60218*10⁻¹³ Joule

    Number of atoms in a 2.6 kg sample mass = (2.6/0.235) * 6.02214076*10²³

    ⇒Number of atoms in a 2.6 kg sample mass = 66.627*10²³ atoms

    Change in energy = Change in mass / (speed of light) ²

    ΔE = Δmc²

    ⇒200*1.60218*10⁻¹³*66.627*10²³ = Δm * (3*10⁸) ²

    ⇒Δm = 200*1.60218*10⁻¹³*66.627*10²³ / (3*10⁸) ²

    ⇒Δm = 2372.187708*10⁻⁶ kg

    ∴Change in mass = 0.002372187708 kg
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