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5 December, 09:48

Block A weighs 12 N and has an apparent weight of 8 N when completely submerged in an ideal fluid. Block B weighs 20 N and has an apparent weight of 12 N when completely submerged in the same ideal fluid.

The ratio of the densities A / B equals:

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  1. 5 December, 10:08
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    density of block A to density of block B = 2 / 3

    Also density of block B to density of block A = 3 / 2

    Explanation:

    Given:

    Weight of block A = 12 N

    Apparent weight of block A = 8 N Weight of block B = 20 N

    Apparent weight of block B = 12 N

    Upthrust in the fluid = density of block x volume of fluid x gravity

    In equilibrium condition; upthrust in fluid = weight of the block in fluid

    Weight of the block = density of block x volume of fluid x gravity

    For constant volume of the fluid;

    Volume = Weight / (density x gravity)

    For block A: weight when completely submerged in fluid = 8N

    Volume = (8) / (density of A x gravity)

    For block B

    Volume = (12) / (density of B x gravity)

    At same fluid volume:

    (8) / (density of A x gravity) = (12) / (density of B x gravity)

    (8/12) = (density of A x gravity) / (density of B x gravity)

    density A / density B = 2 / 3

    Therefore, density of block A to density of block B is 2/3.

    Also density of block B to density of block A is 3 / 2
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