A car traveling at 27 m/s starts to decelerate steadily. It comes to a complete stop in 14 seconds. What is its acceleration?

Question

Physics

Josiah Vincent

16 June, 22:14

A car traveling at 27 m/s starts to decelerate steadily. It comes to a complete stop in 14 seconds. What is its acceleration?

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Answers (1)

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Lorelai Hahn · Answer 1

You will need to use this formula:

V = Vo + a x t

V - Final velocity / / If it comes to a complete stop, it will be 0 m/s.

Vo - Initial velocity = 27 m/s

a - Acceleration = ? m/s^2 / / All units are in S. I

t - Time = 14 secs

So:

-> 0 = 27 + a x 14

-> 14a + 27 = 0

-> 14a = - 27

-> a = - 27/14

-> a = - 1.928 ... m/s^2

Rounding to the nearest hundredth: - 1.93 m/s^2.

Answer: The acceleration of the car is - 1.93 m/s^2.