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31 May, 16:27

What is the magnitude of the acceleration a of the chair? What is the magnitude of the normal force fn acting on the chair?

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  1. 31 May, 17:57
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    1. The acceleration of the chair is 0.64 m/s²

    2. The normal force acting on the chair is 523.6 N

    Explanation:

    Let's list out the parameters given us:

    mass = 45 kg, F = 144 N, θ = 35°, F (f) = 89 N

    Solving for the horizontal component of the Force, we use the formula

    F (hor) = F * cos θ = 144 * cos 35°

    F (hor) = 117.96 N

    F (hor) = 118 N

    The friction force is acting upon the chair in the opposite direction of the f (hor) & must be accounted for

    F (net) = F (hor) - F (f)

    F (net) = 118 - 89 = 29

    F (net) = 29N

    F (net) = mg

    g = F (net) : m = 29 : 45

    g = 0.64 m/s²

    F (norm) = F (chair) + F (ver)

    F (chair) = mg

    where g = acceleration due to gravity = 9.8 m/s²

    F (chair) = 45 * 9.8 = 441 N

    F (ver) = F * sin θ = 144 * sin 35°

    F (ver) = 82.6 N

    F (norm) = 441 + 82.6 = 523.6

    F (norm) = 523.6 N
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