A person pulls a toboggan for a distance of 13.2m along the snow with a rope directed 31 degree above the snow then tension in the rope is 95N how much work is done on the toboggan by the tension force

W = 1074.88 J = 1.07 KJ

Explanation:

The work done on an object by a force is given as the dot product of the force, with the displacement. So, the formula for work done in this case will be:

W = F. d

W = F d Cos θ

where,

W = Work done by tension force = ?

F = Magnitude of tension force = 95 N

d = displacement covered = 13.2 m

θ = Angle of force with horizontal = 31°

Therefore, using the values in equation, we get:

W = (95 N) (13.2 m) (Cos 31°)

W = 1074.88 J = 1.07 KJ